2x^2+32=6 eching

$$2 { x }^{ 2 } +32=6$$

x uchun yechish (complex solution)

$$x=-\sqrt{13}i\approx -0-3,605551275i$$

$$x=\sqrt{13}i\approx 3,605551275i$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 32 ni ayirish.

$$2x^{2}=6-32$$

-26 olish uchun 6 dan 32 ni ayirish.

$$2x^{2}=-26$$

Ikki tarafini 2 ga bo‘ling.

$$x^{2}=\frac{-26}{2}$$

-13 ni olish uchun -26 ni 2 ga bo‘ling.

$$x^{2}=-13$$

Tenglama yechildi.

$$x=\sqrt{13}i x=-\sqrt{13}i$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 6 ni ayirish.

$$2x^{2}+32-6=0$$

26 olish uchun 32 dan 6 ni ayirish.

$$2x^{2}+26=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 2 ni a, 0 ni b va 26 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 2\times 26}}{2\times 2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 2\times 26}}{2\times 2}$$

-4 ni 2 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-8\times 26}}{2\times 2}$$

-8 ni 26 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-208}}{2\times 2}$$

-208 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4\sqrt{13}i}{2\times 2}$$

2 ni 2 marotabaga ko'paytirish.

$$x=\frac{0±4\sqrt{13}i}{4}$$

x=\frac{0±4\sqrt{13}i}{4} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{13}i$$

x=\frac{0±4\sqrt{13}i}{4} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{13}i$$

Tenglama yechildi.

$$x=\sqrt{13}i x=-\sqrt{13}i$$