2{left(-sqrt{2}-1right)}^2-2 eching

$$2 { \left(- \sqrt{ 2 } -1 \right) }^{ 2 } -2$$

Baholash

$$4\left(\sqrt{2}+1\right)\approx 9,656854249$$

Yechim qadamlari

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(-\sqrt{2}-1\right)^{2} kengaytirilishi uchun ishlating.

$$2\left(\left(-\sqrt{2}\right)^{2}-2\left(-\sqrt{2}\right)+1\right)-2$$

2 daraja ko‘rsatkichini -\sqrt{2} ga hisoblang va \left(\sqrt{2}\right)^{2} ni qiymatni oling.

$$2\left(\left(\sqrt{2}\right)^{2}-2\left(-\sqrt{2}\right)+1\right)-2$$

2 hosil qilish uchun -2 va -1 ni ko'paytirish.

$$2\left(\left(\sqrt{2}\right)^{2}+2\sqrt{2}+1\right)-2$$

2 ga \left(\sqrt{2}\right)^{2}+2\sqrt{2}+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2\left(\sqrt{2}\right)^{2}+4\sqrt{2}+2-2$$

\sqrt{2} kvadrati – 2.

$$2\times 2+4\sqrt{2}+2-2$$

4 hosil qilish uchun 2 va 2 ni ko'paytirish.

$$4+4\sqrt{2}+2-2$$

6 olish uchun 4 va 2'ni qo'shing.

$$6+4\sqrt{2}-2$$

4 olish uchun 6 dan 2 ni ayirish.

$$4+4\sqrt{2}$$

Kengaytirish

$$4 \sqrt{2} + 4 = 9,656854249$$

Yechim qadamlari

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(-\sqrt{2}-1\right)^{2} kengaytirilishi uchun ishlating.

$$2\left(\left(-\sqrt{2}\right)^{2}-2\left(-\sqrt{2}\right)+1\right)-2$$

2 daraja ko‘rsatkichini -\sqrt{2} ga hisoblang va \left(\sqrt{2}\right)^{2} ni qiymatni oling.

$$2\left(\left(\sqrt{2}\right)^{2}-2\left(-\sqrt{2}\right)+1\right)-2$$

2 hosil qilish uchun -2 va -1 ni ko'paytirish.

$$2\left(\left(\sqrt{2}\right)^{2}+2\sqrt{2}+1\right)-2$$

2 ga \left(\sqrt{2}\right)^{2}+2\sqrt{2}+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2\left(\sqrt{2}\right)^{2}+4\sqrt{2}+2-2$$

\sqrt{2} kvadrati – 2.

$$2\times 2+4\sqrt{2}+2-2$$

4 hosil qilish uchun 2 va 2 ni ko'paytirish.

$$4+4\sqrt{2}+2-2$$

6 olish uchun 4 va 2'ni qo'shing.

$$6+4\sqrt{2}-2$$

4 olish uchun 6 dan 2 ni ayirish.

$$4+4\sqrt{2}$$