2sqrt{3}-11^2-(sqrt{3}+2)^2 eching

$$2 \sqrt { 3 } - 11 ^ { 2 } - ( \sqrt { 3 } + 2 ) ^ { 2 }$$

Baholash

$$-2\sqrt{3}-128\approx -131,464101615$$

Yechim qadamlari

2 daraja ko‘rsatkichini 11 ga hisoblang va 121 ni qiymatni oling.

$$2\sqrt{3}-121-\left(\sqrt{3}+2\right)^{2}$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(\sqrt{3}+2\right)^{2} kengaytirilishi uchun ishlating.

$$2\sqrt{3}-121-\left(\left(\sqrt{3}\right)^{2}+4\sqrt{3}+4\right)$$

\sqrt{3} kvadrati – 3.

$$2\sqrt{3}-121-\left(3+4\sqrt{3}+4\right)$$

7 olish uchun 3 va 4'ni qo'shing.

$$2\sqrt{3}-121-\left(7+4\sqrt{3}\right)$$

7+4\sqrt{3} teskarisini topish uchun har birining teskarisini toping.

$$2\sqrt{3}-121-7-4\sqrt{3}$$

-128 olish uchun -121 dan 7 ni ayirish.

$$2\sqrt{3}-128-4\sqrt{3}$$

-2\sqrt{3} ni olish uchun 2\sqrt{3} va -4\sqrt{3} ni birlashtirish.

$$-2\sqrt{3}-128$$