2*(3x+4)-2*(5x+2)=3*(2x+2)+4*(4x+4) eching

$$2 \cdot ( 3 x + 4 ) - 2 \cdot ( 5 x + 2 ) = 3 \cdot ( 2 x + 2 ) + 4 \cdot ( 4 x + 4 )$$

x uchun yechish

$$x=-\frac{9}{13}\approx -0,692307692$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 ga 3x+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$6x+8-2\left(5x+2\right)=3\left(2x+2\right)+4\left(4x+4\right)$$

-2 ga 5x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$6x+8-10x-4=3\left(2x+2\right)+4\left(4x+4\right)$$

-4x ni olish uchun 6x va -10x ni birlashtirish.

$$-4x+8-4=3\left(2x+2\right)+4\left(4x+4\right)$$

4 olish uchun 8 dan 4 ni ayirish.

$$-4x+4=3\left(2x+2\right)+4\left(4x+4\right)$$

3 ga 2x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-4x+4=6x+6+4\left(4x+4\right)$$

4 ga 4x+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-4x+4=6x+6+16x+16$$

22x ni olish uchun 6x va 16x ni birlashtirish.

$$-4x+4=22x+6+16$$

22 olish uchun 6 va 16'ni qo'shing.

$$-4x+4=22x+22$$

Ikkala tarafdan 22x ni ayirish.

$$-4x+4-22x=22$$

-26x ni olish uchun -4x va -22x ni birlashtirish.

$$-26x+4=22$$

Ikkala tarafdan 4 ni ayirish.

$$-26x=22-4$$

18 olish uchun 22 dan 4 ni ayirish.

$$-26x=18$$

Ikki tarafini -26 ga bo‘ling.

$$x=\frac{18}{-26}$$

\frac{18}{-26} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=-\frac{9}{13}$$