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2^{3x-6}=32
Tenglamani yechish uchun eksponent va logaritmlarning qoidalaridan foydalanish.
\log(2^{3x-6})=\log(32)
Tenglamaning ikkala tarafiga tegishli logaritmni chiqarish.
\left(3x-6\right)\log(2)=\log(32)
Darajaga ko'tarigan logaritm raqami raqam logaritmining darajasidir.
3x-6=\frac{\log(32)}{\log(2)}
Ikki tarafini \log(2) ga bo‘ling.
3x-6=\log_{2}\left(32\right)
Asosiy tenglamani almashtirish orqali \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
3x=5-\left(-6\right)
6 ni tenglamaning ikkala tarafiga qo'shish.
x=\frac{11}{3}
Ikki tarafini 3 ga bo‘ling.