2+x^2=5 eching

$$2 + x ^ { 2 } = 5$$

x uchun yechish

$$x=\sqrt{3}\approx 1,732050808$$

$$x=-\sqrt{3}\approx -1,732050808$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 2 ni ayirish.

$$x^{2}=5-2$$

3 olish uchun 5 dan 2 ni ayirish.

$$x^{2}=3$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{3} x=-\sqrt{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 5 ni ayirish.

$$2+x^{2}-5=0$$

-3 olish uchun 2 dan 5 ni ayirish.

$$-3+x^{2}=0$$

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$x^{2}-3=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -3 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-3\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-3\right)}}{2}$$

-4 ni -3 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{12}}{2}$$

12 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{3}}{2}$$

x=\frac{0±2\sqrt{3}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{3}$$

x=\frac{0±2\sqrt{3}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{3}$$

Tenglama yechildi.

$$x=\sqrt{3} x=-\sqrt{3}$$