1x+2y=30y*35z eching

$$1x+2y = 30y \times 35z$$

y uchun yechish (complex solution)

$$\left\{\begin{matrix}y=-\frac{x}{2\left(1-525z\right)}\text{, }&z\neq \frac{1}{525}\\y\in \mathrm{C}\text{, }&x=0\text{ and }z=\frac{1}{525}\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

1050 hosil qilish uchun 30 va 35 ni ko'paytirish.

$$1x+2y=1050yz$$

Ikkala tarafdan 1050yz ni ayirish.

$$1x+2y-1050yz=0$$

Ikkala tarafdan 1x ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$2y-1050yz=-x$$

y'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(2-1050z\right)y=-x$$

Ikki tarafini 2-1050z ga bo‘ling.

$$\frac{\left(2-1050z\right)y}{2-1050z}=-\frac{x}{2-1050z}$$

2-1050z ga bo'lish 2-1050z ga ko'paytirishni bekor qiladi.

$$y=-\frac{x}{2-1050z}$$

-x ni 2-1050z ga bo'lish.

$$y=-\frac{x}{2\left(1-525z\right)}$$

x uchun yechish

$$x=2y\left(525z-1\right)$$

Yechim qadamlari

1050 hosil qilish uchun 30 va 35 ni ko'paytirish.

$$1x+2y=1050yz$$

Ikkala tarafdan 2y ni ayirish.

$$1x=1050yz-2y$$

Shartlarni qayta saralash.

$$x=1050yz-2y$$

y uchun yechish

$$\left\{\begin{matrix}y=-\frac{x}{2\left(1-525z\right)}\text{, }&z\neq \frac{1}{525}\\y\in \mathrm{R}\text{, }&x=0\text{ and }z=\frac{1}{525}\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

1050 hosil qilish uchun 30 va 35 ni ko'paytirish.

$$1x+2y=1050yz$$

Ikkala tarafdan 1050yz ni ayirish.

$$1x+2y-1050yz=0$$

Ikkala tarafdan 1x ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$2y-1050yz=-x$$

y'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(2-1050z\right)y=-x$$

Ikki tarafini 2-1050z ga bo‘ling.

$$\frac{\left(2-1050z\right)y}{2-1050z}=-\frac{x}{2-1050z}$$

2-1050z ga bo'lish 2-1050z ga ko'paytirishni bekor qiladi.

$$y=-\frac{x}{2-1050z}$$

-x ni 2-1050z ga bo'lish.

$$y=-\frac{x}{2\left(1-525z\right)}$$