19a^3-12x+4=0 eching

$$19 a ^ { 3 } - 12 x + 4 = 0$$

x uchun yechish

$$x=\frac{19a^{3}}{12}+\frac{1}{3}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan 19a^{3} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-12x+4=-19a^{3}$$

Ikkala tarafdan 4 ni ayirish.

$$-12x=-19a^{3}-4$$

Ikki tarafini -12 ga bo‘ling.

$$\frac{-12x}{-12}=\frac{-19a^{3}-4}{-12}$$

-12 ga bo'lish -12 ga ko'paytirishni bekor qiladi.

$$x=\frac{-19a^{3}-4}{-12}$$

-19a^{3}-4 ni -12 ga bo'lish.

$$x=\frac{19a^{3}}{12}+\frac{1}{3}$$

a uchun yechish (complex solution)

$$a=\frac{19^{\frac{2}{3}}e^{\frac{2\pi i}{3}}\sqrt[3]{12x-4}}{19}$$

$$a=\frac{19^{\frac{2}{3}}\sqrt[3]{12x-4}}{19}$$

$$a=\frac{19^{\frac{2}{3}}e^{\frac{4\pi i}{3}}\sqrt[3]{12x-4}}{19}$$

a uchun yechish

$$a=\frac{19^{\frac{2}{3}}\sqrt[3]{12x-4}}{19}$$