18^2-5x+sqrt{5}=x eching

$$18 ^ { 2 } - 5 x + \sqrt { 5 } = x$$

x uchun yechish

$$x = \frac{\sqrt{5} + 324}{6} \approx 54,372677996$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 18 ga hisoblang va 324 ni qiymatni oling.

$$324-5x+\sqrt{5}=x$$

Ikkala tarafdan x ni ayirish.

$$324-5x+\sqrt{5}-x=0$$

-6x ni olish uchun -5x va -x ni birlashtirish.

$$324-6x+\sqrt{5}=0$$

Ikkala tarafdan 324 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-6x+\sqrt{5}=-324$$

Ikkala tarafdan \sqrt{5} ni ayirish.

$$-6x=-324-\sqrt{5}$$

Tenglama standart shaklda.

$$-6x=-\sqrt{5}-324$$

Ikki tarafini -6 ga bo‘ling.

$$\frac{-6x}{-6}=\frac{-\sqrt{5}-324}{-6}$$

-6 ga bo'lish -6 ga ko'paytirishni bekor qiladi.

$$x=\frac{-\sqrt{5}-324}{-6}$$

-324-\sqrt{5} ni -6 ga bo'lish.

$$x=\frac{\sqrt{5}}{6}+54$$