16+x^2=left(8-xright)^2 eching

$$16+ { x }^{ 2 } = { \left(8-x \right) }^{ 2 }$$

x uchun yechish

$$x=3$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(8-x\right)^{2} kengaytirilishi uchun ishlating.

$$16+x^{2}=64-16x+x^{2}$$

16x ni ikki tarafga qo’shing.

$$16+x^{2}+16x=64+x^{2}$$

Ikkala tarafdan x^{2} ni ayirish.

$$16+x^{2}+16x-x^{2}=64$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$16+16x=64$$

Ikkala tarafdan 16 ni ayirish.

$$16x=64-16$$

48 olish uchun 64 dan 16 ni ayirish.

$$16x=48$$

Ikki tarafini 16 ga bo‘ling.

$$x=\frac{48}{16}$$

3 ni olish uchun 48 ni 16 ga bo‘ling.

$$x=3$$