16y^2+7y+8 eching

$$16 y ^ { 2 } + 7 y + 8$$

y ga nisbatan hosilani topish

$$32y+7$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$2\times 16y^{2-1}+7y^{1-1}$$

2 ni 16 marotabaga ko'paytirish.

$$32y^{2-1}+7y^{1-1}$$

2 dan 1 ni ayirish.

$$32y^{1}+7y^{1-1}$$

1 dan 1 ni ayirish.

$$32y^{1}+7y^{0}$$

Har qanday t sharti uchun t^{1}=t.

$$32y+7y^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$32y+7\times 1$$

Har qanday t sharti uchun t\times 1=t va 1t=t.

$$32y+7$$

Baholash

$$16y^{2}+7y+8$$