16x^2+x-75 eching

$$16 { x }^{ 2 } +x-75$$

Omil

$$16\left(x-\frac{-\sqrt{4801}-1}{32}\right)\left(x-\frac{\sqrt{4801}-1}{32}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$16x^{2}+x-75=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-1±\sqrt{1^{2}-4\times 16\left(-75\right)}}{2\times 16}$$

1 kvadratini chiqarish.

$$x=\frac{-1±\sqrt{1-4\times 16\left(-75\right)}}{2\times 16}$$

-4 ni 16 marotabaga ko'paytirish.

$$x=\frac{-1±\sqrt{1-64\left(-75\right)}}{2\times 16}$$

-64 ni -75 marotabaga ko'paytirish.

$$x=\frac{-1±\sqrt{1+4800}}{2\times 16}$$

1 ni 4800 ga qo'shish.

$$x=\frac{-1±\sqrt{4801}}{2\times 16}$$

2 ni 16 marotabaga ko'paytirish.

$$x=\frac{-1±\sqrt{4801}}{32}$$

x=\frac{-1±\sqrt{4801}}{32} tenglamasini yeching, bunda ± musbat. -1 ni \sqrt{4801} ga qo'shish.

$$x=\frac{\sqrt{4801}-1}{32}$$

x=\frac{-1±\sqrt{4801}}{32} tenglamasini yeching, bunda ± manfiy. -1 dan \sqrt{4801} ni ayirish.

$$x=\frac{-\sqrt{4801}-1}{32}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-1+\sqrt{4801}}{32} ga va x_{2} uchun \frac{-1-\sqrt{4801}}{32} ga bo‘ling.

$$16x^{2}+x-75=16\left(x-\frac{\sqrt{4801}-1}{32}\right)\left(x-\frac{-\sqrt{4801}-1}{32}\right)$$

Baholash

$$16x^{2}+x-75$$