14x-(3x+5)^2-(10-x)(2x+8) eching

$$14 x - ( 3 x + 5 ) ^ { 2 } - ( 10 - x ) ( 2 x + 8 )$$

Baholash

$$-7x^{2}-28x-105$$

Yechim qadamlari

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(3x+5\right)^{2} kengaytirilishi uchun ishlating.

$$14x-\left(9x^{2}+30x+25\right)-\left(10-x\right)\left(2x+8\right)$$

9x^{2}+30x+25 teskarisini topish uchun har birining teskarisini toping.

$$14x-9x^{2}-30x-25-\left(10-x\right)\left(2x+8\right)$$

-16x ni olish uchun 14x va -30x ni birlashtirish.

$$-16x-9x^{2}-25-\left(10-x\right)\left(2x+8\right)$$

10-x ga 2x+8 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$-16x-9x^{2}-25-\left(12x+80-2x^{2}\right)$$

12x+80-2x^{2} teskarisini topish uchun har birining teskarisini toping.

$$-16x-9x^{2}-25-12x-80+2x^{2}$$

-28x ni olish uchun -16x va -12x ni birlashtirish.

$$-28x-9x^{2}-25-80+2x^{2}$$

-105 olish uchun -25 dan 80 ni ayirish.

$$-28x-9x^{2}-105+2x^{2}$$

-7x^{2} ni olish uchun -9x^{2} va 2x^{2} ni birlashtirish.

$$-28x-7x^{2}-105$$

Kengaytirish

$$-7x^{2}-28x-105$$

Yechim qadamlari

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(3x+5\right)^{2} kengaytirilishi uchun ishlating.

$$14x-\left(9x^{2}+30x+25\right)-\left(10-x\right)\left(2x+8\right)$$

9x^{2}+30x+25 teskarisini topish uchun har birining teskarisini toping.

$$14x-9x^{2}-30x-25-\left(10-x\right)\left(2x+8\right)$$

-16x ni olish uchun 14x va -30x ni birlashtirish.

$$-16x-9x^{2}-25-\left(10-x\right)\left(2x+8\right)$$

10-x ga 2x+8 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$-16x-9x^{2}-25-\left(12x+80-2x^{2}\right)$$

12x+80-2x^{2} teskarisini topish uchun har birining teskarisini toping.

$$-16x-9x^{2}-25-12x-80+2x^{2}$$

-28x ni olish uchun -16x va -12x ni birlashtirish.

$$-28x-9x^{2}-25-80+2x^{2}$$

-105 olish uchun -25 dan 80 ni ayirish.

$$-28x-9x^{2}-105+2x^{2}$$

-7x^{2} ni olish uchun -9x^{2} va 2x^{2} ni birlashtirish.

$$-28x-7x^{2}-105$$