13-4x^2>0 eching

$$13 - 4 x ^ { 2 } > 0$$

x uchun yechish

$$x\in \left(-\frac{\sqrt{13}}{2},\frac{\sqrt{13}}{2}\right)$$

Yechim qadamlari

13-4x^{2} musbatida eng katta quvvatni koeffitsientini aniqlash uchun tengsizlikni -1 ga koʻpaytiring. -1 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$-13+4x^{2}<0$$

\frac{13}{4} ni ikki tarafga qo’shing.

$$x^{2}<\frac{13}{4}$$

\frac{13}{4} ning kvadrat ildizini hisoblab, \frac{\sqrt{13}}{2} natijaga ega bo‘ling. \frac{13}{4} ni \left(\frac{\sqrt{13}}{2}\right)^{2} sifatida qaytadan yozish.

$$x^{2}<\left(\frac{\sqrt{13}}{2}\right)^{2}$$

Tengsizlikda |x|<\frac{\sqrt{13}}{2} bor.

$$|x|<\frac{\sqrt{13}}{2}$$

|x|<\frac{\sqrt{13}}{2} ni x\in \left(-\frac{\sqrt{13}}{2},\frac{\sqrt{13}}{2}\right) sifatida qaytadan yozish.

$$x\in \left(-\frac{\sqrt{13}}{2},\frac{\sqrt{13}}{2}\right)$$