13x^2+26x eching

$$13 { x }^{ 2 } +26x$$

Omil

$$13x\left(x+2\right)$$

Yechim qadamlari

13 omili.

$$13\left(x^{2}+2x\right)$$

Hisoblang: x^{2}+2x. x omili.

$$x\left(x+2\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$13x\left(x+2\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$13x^{2}+26x=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-26±\sqrt{26^{2}}}{2\times 13}$$

26^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-26±26}{2\times 13}$$

2 ni 13 marotabaga ko'paytirish.

$$x=\frac{-26±26}{26}$$

x=\frac{-26±26}{26} tenglamasini yeching, bunda ± musbat. -26 ni 26 ga qo'shish.

$$x=\frac{0}{26}$$

0 ni 26 ga bo'lish.

$$x=0$$

x=\frac{-26±26}{26} tenglamasini yeching, bunda ± manfiy. -26 dan 26 ni ayirish.

$$x=-\frac{52}{26}$$

-52 ni 26 ga bo'lish.

$$x=-2$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun -2 ga bo‘ling.

$$13x^{2}+26x=13x\left(x-\left(-2\right)\right)$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$13x^{2}+26x=13x\left(x+2\right)$$

Baholash

$$13x\left(x+2\right)$$