12-x(2x+1)=3x-2x^2+7 eching

$$12-x(2x+1)=3x-2 { x }^{ 2 } +7$$

x uchun yechish

$$x = \frac{5}{4} = 1\frac{1}{4} = 1,25$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x ga 2x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$12-\left(2x^{2}+x\right)=3x-2x^{2}+7$$

2x^{2}+x teskarisini topish uchun har birining teskarisini toping.

$$12-2x^{2}-x=3x-2x^{2}+7$$

Ikkala tarafdan 3x ni ayirish.

$$12-2x^{2}-x-3x=-2x^{2}+7$$

-4x ni olish uchun -x va -3x ni birlashtirish.

$$12-2x^{2}-4x=-2x^{2}+7$$

2x^{2} ni ikki tarafga qo’shing.

$$12-2x^{2}-4x+2x^{2}=7$$

0 ni olish uchun -2x^{2} va 2x^{2} ni birlashtirish.

$$12-4x=7$$

Ikkala tarafdan 12 ni ayirish.

$$-4x=7-12$$

-5 olish uchun 7 dan 12 ni ayirish.

$$-4x=-5$$

Ikki tarafini -4 ga bo‘ling.

$$x=\frac{-5}{-4}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-5}{-4} kasrini \frac{5}{4} ga soddalashtirish mumkin.

$$x=\frac{5}{4}$$