12x^2+x eching

$$12 { x }^{ 2 } +x$$

Omil

$$x\left(12x+1\right)$$

Yechim qadamlari

x omili.

$$x\left(12x+1\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$12x^{2}+x=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-1±\sqrt{1^{2}}}{2\times 12}$$

1^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-1±1}{2\times 12}$$

2 ni 12 marotabaga ko'paytirish.

$$x=\frac{-1±1}{24}$$

x=\frac{-1±1}{24} tenglamasini yeching, bunda ± musbat. -1 ni 1 ga qo'shish.

$$x=\frac{0}{24}$$

0 ni 24 ga bo'lish.

$$x=0$$

x=\frac{-1±1}{24} tenglamasini yeching, bunda ± manfiy. -1 dan 1 ni ayirish.

$$x=-\frac{2}{24}$$

\frac{-2}{24} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=-\frac{1}{12}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun -\frac{1}{12} ga bo‘ling.

$$12x^{2}+x=12x\left(x-\left(-\frac{1}{12}\right)\right)$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$12x^{2}+x=12x\left(x+\frac{1}{12}\right)$$

Umumiy maxrajni topib va hisoblovchini qo'shish orqali \frac{1}{12} ni x ga qo'shing. So'ngra agar imkoni bo'lsa kasrni eng kam shartga qisqartiring.

$$12x^{2}+x=12x\times \frac{12x+1}{12}$$

12 va 12 ichida eng katta umumiy 12 faktorini bekor qiling.

$$12x^{2}+x=x\left(12x+1\right)$$

Baholash

$$x\left(12x+1\right)$$