11x=9x/5y+13y eching

$$11x= \frac{ 9x }{ 5y } +13y$$

x uchun yechish

$$x=\frac{65y^{2}}{55y-9}$$

$$y\neq \frac{9}{55}\text{ and }y\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 5y ga ko'paytirish.

$$11x\times 5y=9x+13y\times 5y$$

55 hosil qilish uchun 11 va 5 ni ko'paytirish.

$$55xy=9x+13y\times 5y$$

y^{2} hosil qilish uchun y va y ni ko'paytirish.

$$55xy=9x+13y^{2}\times 5$$

65 hosil qilish uchun 13 va 5 ni ko'paytirish.

$$55xy=9x+65y^{2}$$

Ikkala tarafdan 9x ni ayirish.

$$55xy-9x=65y^{2}$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(55y-9\right)x=65y^{2}$$

Ikki tarafini 55y-9 ga bo‘ling.

$$\frac{\left(55y-9\right)x}{55y-9}=\frac{65y^{2}}{55y-9}$$

55y-9 ga bo'lish 55y-9 ga ko'paytirishni bekor qiladi.

$$x=\frac{65y^{2}}{55y-9}$$

y uchun yechish (complex solution)

$$y=-\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}$$

$$y=\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}\text{, }x\neq 0$$

y uchun yechish

$$y=-\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}$$

$$y=\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}\text{, }x\geq \frac{468}{605}\text{ or }x<0$$