112(1+x)^2=288 eching

$$112 ( 1 + x ) ^ { 2 } = 288$$

x uchun yechish

$$x=\frac{3\sqrt{14}}{7}-1\approx 0,603567451$$

$$x=-\frac{3\sqrt{14}}{7}-1\approx -2,603567451$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikki tarafini 112 ga bo‘ling.

$$\frac{112\left(x+1\right)^{2}}{112}=\frac{288}{112}$$

112 ga bo'lish 112 ga ko'paytirishni bekor qiladi.

$$\left(x+1\right)^{2}=\frac{288}{112}$$

\frac{288}{112} ulushini 16 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\left(x+1\right)^{2}=\frac{18}{7}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x+1=\frac{3\sqrt{14}}{7} x+1=-\frac{3\sqrt{14}}{7}$$

Tenglamaning ikkala tarafidan 1 ni ayirish.

$$x+1-1=\frac{3\sqrt{14}}{7}-1 x+1-1=-\frac{3\sqrt{14}}{7}-1$$

O‘zidan 1 ayirilsa 0 qoladi.

$$x=\frac{3\sqrt{14}}{7}-1 x=-\frac{3\sqrt{14}}{7}-1$$