11=x+13*40/40+x eching

$$11= \frac{ x+13 \times 40 }{ 40+x }$$

x uchun yechish

$$x=8$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x qiymati -40 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini x+40 ga ko'paytirish.

$$11\left(x+40\right)=x+13\times 40$$

11 ga x+40 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$11x+440=x+13\times 40$$

520 hosil qilish uchun 13 va 40 ni ko'paytirish.

$$11x+440=x+520$$

Ikkala tarafdan x ni ayirish.

$$11x+440-x=520$$

10x ni olish uchun 11x va -x ni birlashtirish.

$$10x+440=520$$

Ikkala tarafdan 440 ni ayirish.

$$10x=520-440$$

80 olish uchun 520 dan 440 ni ayirish.

$$10x=80$$

Ikki tarafini 10 ga bo‘ling.

$$x=\frac{80}{10}$$

8 ni olish uchun 80 ni 10 ga bo‘ling.

$$x=8$$