1000^2+p^2=100 eching

$$1000 ^ { 2 } + p ^ { 2 } = 100$$

p uchun yechish

$$p=-30\sqrt{1111}i\approx -0-999,94999875i$$

$$p=30\sqrt{1111}i\approx 999,94999875i$$

Kvadrat ildizini topish bo'yicha qadamlar

2 daraja ko‘rsatkichini 1000 ga hisoblang va 1000000 ni qiymatni oling.

$$1000000+p^{2}=100$$

Ikkala tarafdan 1000000 ni ayirish.

$$p^{2}=100-1000000$$

-999900 olish uchun 100 dan 1000000 ni ayirish.

$$p^{2}=-999900$$

Tenglama yechildi.

$$p=30\sqrt{1111}i p=-30\sqrt{1111}i$$

Kvadrat tenglamalaridan foydalanish qoidalari

2 daraja ko‘rsatkichini 1000 ga hisoblang va 1000000 ni qiymatni oling.

$$1000000+p^{2}=100$$

Ikkala tarafdan 100 ni ayirish.

$$1000000+p^{2}-100=0$$

999900 olish uchun 1000000 dan 100 ni ayirish.

$$999900+p^{2}=0$$

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$p^{2}+999900=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va 999900 ni c bilan almashtiring.

$$p=\frac{0±\sqrt{0^{2}-4\times 999900}}{2}$$

0 kvadratini chiqarish.

$$p=\frac{0±\sqrt{-4\times 999900}}{2}$$

-4 ni 999900 marotabaga ko'paytirish.

$$p=\frac{0±\sqrt{-3999600}}{2}$$

-3999600 ning kvadrat ildizini chiqarish.

$$p=\frac{0±60\sqrt{1111}i}{2}$$

p=\frac{0±60\sqrt{1111}i}{2} tenglamasini yeching, bunda ± musbat.

$$p=30\sqrt{1111}i$$

p=\frac{0±60\sqrt{1111}i}{2} tenglamasini yeching, bunda ± manfiy.

$$p=-30\sqrt{1111}i$$

Tenglama yechildi.

$$p=30\sqrt{1111}i p=-30\sqrt{1111}i$$