10-(-3(x-7)+5x)+40=5(4-3x eching

$$10-(-3(x-7)+5x)+40=5(4-3x$$

x uchun yechish

$$x=-\frac{9}{13}\approx -0,692307692$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-3 ga x-7 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$10-\left(-3x+21+5x\right)+40=5\left(4-3x\right)$$

2x ni olish uchun -3x va 5x ni birlashtirish.

$$10-\left(2x+21\right)+40=5\left(4-3x\right)$$

2x+21 teskarisini topish uchun har birining teskarisini toping.

$$10-2x-21+40=5\left(4-3x\right)$$

-11 olish uchun 10 dan 21 ni ayirish.

$$-11-2x+40=5\left(4-3x\right)$$

29 olish uchun -11 va 40'ni qo'shing.

$$29-2x=5\left(4-3x\right)$$

5 ga 4-3x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$29-2x=20-15x$$

15x ni ikki tarafga qo’shing.

$$29-2x+15x=20$$

13x ni olish uchun -2x va 15x ni birlashtirish.

$$29+13x=20$$

Ikkala tarafdan 29 ni ayirish.

$$13x=20-29$$

-9 olish uchun 20 dan 29 ni ayirish.

$$13x=-9$$

Ikki tarafini 13 ga bo‘ling.

$$x=\frac{-9}{13}$$

\frac{-9}{13} kasri manfiy belgini olib tashlash bilan -\frac{9}{13} sifatida qayta yozilishi mumkin.

$$x=-\frac{9}{13}$$