10(1000-x)(1+02%x)geq12x eching

$$10(1000-x)(1+02 \% x) \geq 12x$$

x uchun yechish

$$x\leq \frac{5000}{11}$$

Yechim qadamlari

\frac{2}{100} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$10\left(1000-x\right)\left(1+0\times \frac{1}{50}x\right)\geq 12x$$

0 hosil qilish uchun 0 va \frac{1}{50} ni ko'paytirish.

$$10\left(1000-x\right)\left(1+0x\right)\geq 12x$$

Har qanday sonni nolga ko‘paytirsangiz, nol chiqadi.

$$10\left(1000-x\right)\left(1+0\right)\geq 12x$$

1 olish uchun 1 va 0'ni qo'shing.

$$10\left(1000-x\right)\times 1\geq 12x$$

10 hosil qilish uchun 10 va 1 ni ko'paytirish.

$$10\left(1000-x\right)\geq 12x$$

10 ga 1000-x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$10000-10x\geq 12x$$

Ikkala tarafdan 12x ni ayirish.

$$10000-10x-12x\geq 0$$

-22x ni olish uchun -10x va -12x ni birlashtirish.

$$10000-22x\geq 0$$

Ikkala tarafdan 10000 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-22x\geq -10000$$

Ikki tarafini -22 ga bo‘ling. -22 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x\leq \frac{-10000}{-22}$$

\frac{-10000}{-22} ulushini -2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x\leq \frac{5000}{11}$$