10ydiv5^2+24ydiv40 eching

$$10 y \div 5 ^ { 2 } + 24 y \div 40$$

Baholash

$$y$$

Yechim qadamlari

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$\frac{10y}{25}+\frac{24y}{40}$$

\frac{2}{5}y ni olish uchun 10y ni 25 ga bo‘ling.

$$\frac{2}{5}y+\frac{24y}{40}$$

\frac{3}{5}y ni olish uchun 24y ni 40 ga bo‘ling.

$$\frac{2}{5}y+\frac{3}{5}y$$

y ni olish uchun \frac{2}{5}y va \frac{3}{5}y ni birlashtirish.

$$y$$

y ga nisbatan hosilani topish

$$1$$

Derivativ ifodasidan foydalanish qadamlari

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\frac{10y}{25}+\frac{24y}{40})$$

\frac{2}{5}y ni olish uchun 10y ni 25 ga bo‘ling.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\frac{2}{5}y+\frac{24y}{40})$$

\frac{3}{5}y ni olish uchun 24y ni 40 ga bo‘ling.

$$\frac{\mathrm{d}}{\mathrm{d}y}(\frac{2}{5}y+\frac{3}{5}y)$$

y ni olish uchun \frac{2}{5}y va \frac{3}{5}y ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y)$$

ax^{n} hosilasi – nax^{n-1}.

$$y^{1-1}$$

1 dan 1 ni ayirish.

$$y^{0}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$1$$