10j(2x+55^circ)=1050^circ eching

$$10 j ( 2 x + 55 ^ { \circ } ) = 1050 ^ { \circ }$$

j uchun yechish

$$j=\frac{105}{2x+55}$$

$$x\neq -\frac{55}{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

10j ga 2x+55 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$20jx+550j=1050$$

j'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(20x+550\right)j=1050$$

Ikki tarafini 20x+550 ga bo‘ling.

$$\frac{\left(20x+550\right)j}{20x+550}=\frac{1050}{20x+550}$$

20x+550 ga bo'lish 20x+550 ga ko'paytirishni bekor qiladi.

$$j=\frac{1050}{20x+550}$$

1050 ni 20x+550 ga bo'lish.

$$j=\frac{105}{2x+55}$$

x uchun yechish

$$x=-\frac{55}{2}+\frac{105}{2j}$$

$$j\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

10j ga 2x+55 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$20xj+550j=1050$$

Ikkala tarafdan 550j ni ayirish.

$$20xj=1050-550j$$

Tenglama standart shaklda.

$$20jx=1050-550j$$

Ikki tarafini 20j ga bo‘ling.

$$\frac{20jx}{20j}=\frac{1050-550j}{20j}$$

20j ga bo'lish 20j ga ko'paytirishni bekor qiladi.

$$x=\frac{1050-550j}{20j}$$

1050-550j ni 20j ga bo'lish.

$$x=-\frac{55}{2}+\frac{105}{2j}$$