10Dquad1/4(x+1)=1/5(8 eching

$$10 D \quad \frac { 1 } { 4 } ( x + 1 ) = \frac { 1 } { 5 } ( 8$$

D uchun yechish

$$D=\frac{16}{25\left(x+1\right)}$$

$$x\neq -1$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{5}{2} hosil qilish uchun 10 va \frac{1}{4} ni ko'paytirish.

$$\frac{5}{2}D\left(x+1\right)=\frac{1}{5}\times 8$$

\frac{5}{2}D ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{5}{2}Dx+\frac{5}{2}D=\frac{1}{5}\times 8$$

\frac{8}{5} hosil qilish uchun \frac{1}{5} va 8 ni ko'paytirish.

$$\frac{5}{2}Dx+\frac{5}{2}D=\frac{8}{5}$$

D'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(\frac{5}{2}x+\frac{5}{2}\right)D=\frac{8}{5}$$

Tenglama standart shaklda.

$$\frac{5x+5}{2}D=\frac{8}{5}$$

Ikki tarafini \frac{5}{2}x+\frac{5}{2} ga bo‘ling.

$$\frac{2\times \frac{5x+5}{2}D}{5x+5}=\frac{\frac{8}{5}\times 2}{5x+5}$$

\frac{5}{2}x+\frac{5}{2} ga bo'lish \frac{5}{2}x+\frac{5}{2} ga ko'paytirishni bekor qiladi.

$$D=\frac{\frac{8}{5}\times 2}{5x+5}$$

\frac{8}{5} ni \frac{5}{2}x+\frac{5}{2} ga bo'lish.

$$D=\frac{16}{25\left(x+1\right)}$$

x uchun yechish

$$x=-1+\frac{16}{25D}$$

$$D\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{5}{2} hosil qilish uchun 10 va \frac{1}{4} ni ko'paytirish.

$$\frac{5}{2}D\left(x+1\right)=\frac{1}{5}\times 8$$

\frac{5}{2}D ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{5}{2}Dx+\frac{5}{2}D=\frac{1}{5}\times 8$$

\frac{8}{5} hosil qilish uchun \frac{1}{5} va 8 ni ko'paytirish.

$$\frac{5}{2}Dx+\frac{5}{2}D=\frac{8}{5}$$

Ikkala tarafdan \frac{5}{2}D ni ayirish.

$$\frac{5}{2}Dx=\frac{8}{5}-\frac{5}{2}D$$

Tenglama standart shaklda.

$$\frac{5D}{2}x=-\frac{5D}{2}+\frac{8}{5}$$

Ikki tarafini \frac{5}{2}D ga bo‘ling.

$$\frac{2\times \frac{5D}{2}x}{5D}=\frac{2\left(-\frac{5D}{2}+\frac{8}{5}\right)}{5D}$$

\frac{5}{2}D ga bo'lish \frac{5}{2}D ga ko'paytirishni bekor qiladi.

$$x=\frac{2\left(-\frac{5D}{2}+\frac{8}{5}\right)}{5D}$$

\frac{8}{5}-\frac{5D}{2} ni \frac{5}{2}D ga bo'lish.

$$x=-1+\frac{16}{25D}$$