10x^2+3=633 eching

$$10 { x }^{ 2 } +3=633$$

x uchun yechish

$$x=3\sqrt{7}\approx 7,937253933$$

$$x=-3\sqrt{7}\approx -7,937253933$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 3 ni ayirish.

$$10x^{2}=633-3$$

630 olish uchun 633 dan 3 ni ayirish.

$$10x^{2}=630$$

Ikki tarafini 10 ga bo‘ling.

$$x^{2}=\frac{630}{10}$$

63 ni olish uchun 630 ni 10 ga bo‘ling.

$$x^{2}=63$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=3\sqrt{7} x=-3\sqrt{7}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 633 ni ayirish.

$$10x^{2}+3-633=0$$

-630 olish uchun 3 dan 633 ni ayirish.

$$10x^{2}-630=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 10 ni a, 0 ni b va -630 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 10\left(-630\right)}}{2\times 10}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 10\left(-630\right)}}{2\times 10}$$

-4 ni 10 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-40\left(-630\right)}}{2\times 10}$$

-40 ni -630 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{25200}}{2\times 10}$$

25200 ning kvadrat ildizini chiqarish.

$$x=\frac{0±60\sqrt{7}}{2\times 10}$$

2 ni 10 marotabaga ko'paytirish.

$$x=\frac{0±60\sqrt{7}}{20}$$

x=\frac{0±60\sqrt{7}}{20} tenglamasini yeching, bunda ± musbat.

$$x=3\sqrt{7}$$

x=\frac{0±60\sqrt{7}}{20} tenglamasini yeching, bunda ± manfiy.

$$x=-3\sqrt{7}$$

Tenglama yechildi.

$$x=3\sqrt{7} x=-3\sqrt{7}$$