18(1100-x)geq12(1+25%)x eching

$$18(1100-x) \geq 12(1+25 \% )x$$

x uchun yechish

$$x\leq 600$$

Yechim qadamlari

18 ga 1100-x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$19800-18x\geq 12\left(1+\frac{25}{100}\right)x$$

\frac{25}{100} ulushini 25 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$19800-18x\geq 12\left(1+\frac{1}{4}\right)x$$

1 ni \frac{4}{4} kasrga o‘giring.

$$19800-18x\geq 12\left(\frac{4}{4}+\frac{1}{4}\right)x$$

\frac{4}{4} va \frac{1}{4} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$19800-18x\geq 12\times \frac{4+1}{4}x$$

5 olish uchun 4 va 1'ni qo'shing.

$$19800-18x\geq 12\times \frac{5}{4}x$$

12\times \frac{5}{4} ni yagona kasrga aylantiring.

$$19800-18x\geq \frac{12\times 5}{4}x$$

60 hosil qilish uchun 12 va 5 ni ko'paytirish.

$$19800-18x\geq \frac{60}{4}x$$

15 ni olish uchun 60 ni 4 ga bo‘ling.

$$19800-18x\geq 15x$$

Ikkala tarafdan 15x ni ayirish.

$$19800-18x-15x\geq 0$$

-33x ni olish uchun -18x va -15x ni birlashtirish.

$$19800-33x\geq 0$$

Ikkala tarafdan 19800 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-33x\geq -19800$$

Ikki tarafini -33 ga bo‘ling. -33 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x\leq \frac{-19800}{-33}$$

600 ni olish uchun -19800 ni -33 ga bo‘ling.

$$x\leq 600$$