1(x+1)geq3(x+3)-x eching

$$1 ( x + 1 ) \geq 3 ( x + 3 ) - x$$

x uchun yechish

$$x\leq -8$$

Yechim qadamlari

1 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x+1\geq 3\left(x+3\right)-x$$

3 ga x+3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x+1\geq 3x+9-x$$

2x ni olish uchun 3x va -x ni birlashtirish.

$$x+1\geq 2x+9$$

Ikkala tarafdan 2x ni ayirish.

$$x+1-2x\geq 9$$

-x ni olish uchun x va -2x ni birlashtirish.

$$-x+1\geq 9$$

Ikkala tarafdan 1 ni ayirish.

$$-x\geq 9-1$$

8 olish uchun 9 dan 1 ni ayirish.

$$-x\geq 8$$

Ikki tarafini -1 ga bo‘ling. -1 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x\leq -8$$