1quad7-6+|5x-3|=3quad8 eching

$$1 \quad 7 - 6 + | 5 x - 3 | = 3 \quad 8$$

x uchun yechish

$$x=-4$$

$$x = \frac{26}{5} = 5\frac{1}{5} = 5,2$$

Absolyut qiymat ifodasidan foydalanish qadamlari

7 hosil qilish uchun 1 va 7 ni ko'paytirish.

$$7-6+|5x-3|=3\times 8$$

1 olish uchun 7 dan 6 ni ayirish.

$$1+|5x-3|=3\times 8$$

24 hosil qilish uchun 3 va 8 ni ko'paytirish.

$$1+|5x-3|=24$$

Ikkala tarafdan 1 ni ayirish.

$$|5x-3|=24-1$$

23 olish uchun 24 dan 1 ni ayirish.

$$|5x-3|=23$$

Absolyut qiymatning ifodasidan foydalanish.

$$5x-3=23 5x-3=-23$$

3 ni tenglamaning ikkala tarafiga qo'shish.

$$5x=26 5x=-20$$

Ikki tarafini 5 ga bo‘ling.

$$x=\frac{26}{5} x=-4$$