1=b^2-4ac eching

$$1 = b ^ { 2 } - 4 a c$$

a uchun yechish (complex solution)

$$\left\{\begin{matrix}a=\frac{b^{2}-1}{4c}\text{, }&c\neq 0\\a\in \mathrm{C}\text{, }&\left(b=-1\text{ or }b=1\right)\text{ and }c=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$b^{2}-4ac=1$$

Ikkala tarafdan b^{2} ni ayirish.

$$-4ac=1-b^{2}$$

Tenglama standart shaklda.

$$\left(-4c\right)a=1-b^{2}$$

Ikki tarafini -4c ga bo‘ling.

$$\frac{\left(-4c\right)a}{-4c}=\frac{1-b^{2}}{-4c}$$

-4c ga bo'lish -4c ga ko'paytirishni bekor qiladi.

$$a=\frac{1-b^{2}}{-4c}$$

-b^{2}+1 ni -4c ga bo'lish.

$$a=-\frac{1-b^{2}}{4c}$$

a uchun yechish

$$\left\{\begin{matrix}a=\frac{b^{2}-1}{4c}\text{, }&c\neq 0\\a\in \mathrm{R}\text{, }&c=0\text{ and }|b|=1\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$b^{2}-4ac=1$$

Ikkala tarafdan b^{2} ni ayirish.

$$-4ac=1-b^{2}$$

Tenglama standart shaklda.

$$\left(-4c\right)a=1-b^{2}$$

Ikki tarafini -4c ga bo‘ling.

$$\frac{\left(-4c\right)a}{-4c}=\frac{1-b^{2}}{-4c}$$

-4c ga bo'lish -4c ga ko'paytirishni bekor qiladi.

$$a=\frac{1-b^{2}}{-4c}$$

-b^{2}+1 ni -4c ga bo'lish.

$$a=-\frac{1-b^{2}}{4c}$$

b uchun yechish (complex solution)

$$b=-\sqrt{4ac+1}$$

$$b=\sqrt{4ac+1}$$

b uchun yechish

$$b=\sqrt{4ac+1}$$

$$b=-\sqrt{4ac+1}\text{, }\left(c\leq 0\text{ or }a\geq -\frac{1}{4c}\right)\text{ and }\left(c\geq 0\text{ or }a\leq -\frac{1}{4c}\right)$$