1+3^x=10 eching

$$1 + 3 ^ { x } = 10$$

x uchun yechish

$$x=2$$

Logaritm ifodasidan foydalanish qadamlari

Tenglamani yechish uchun eksponent va logaritmlarning qoidalaridan foydalanish.

$$3^{x}+1=10$$

Tenglamaning ikkala tarafidan 1 ni ayirish.

$$3^{x}=9$$

Tenglamaning ikkala tarafiga tegishli logaritmni chiqarish.

$$\log(3^{x})=\log(9)$$

Darajaga ko'tarigan logaritm raqami raqam logaritmining darajasidir.

$$x\log(3)=\log(9)$$

Ikki tarafini \log(3) ga bo‘ling.

$$x=\frac{\log(9)}{\log(3)}$$

Asosiy tenglamani almashtirish orqali \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{3}\left(9\right)$$

x uchun yechish (complex solution)

$$x=\frac{i\times 2\pi n_{1}}{\ln(3)}+2$$

$$n_{1}\in \mathrm{Z}$$