05(sqrt{y^2+10}+y)(sqrt{y^2+10}+y)-2 eching

$$05( \sqrt{ { y }^{ 2 } +10 } +y)( \sqrt{ { y }^{ 2 } +10 } +y)-2$$

Baholash

$$-2$$

Yechim qadamlari

\left(\sqrt{y^{2}+10}+y\right)^{2} hosil qilish uchun \sqrt{y^{2}+10}+y va \sqrt{y^{2}+10}+y ni ko'paytirish.

$$0\times 5\left(\sqrt{y^{2}+10}+y\right)^{2}-2$$

0 hosil qilish uchun 0 va 5 ni ko'paytirish.

$$0\left(\sqrt{y^{2}+10}+y\right)^{2}-2$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(\sqrt{y^{2}+10}+y\right)^{2} kengaytirilishi uchun ishlating.

$$0\left(\left(\sqrt{y^{2}+10}\right)^{2}+2\sqrt{y^{2}+10}y+y^{2}\right)-2$$

2 daraja ko‘rsatkichini \sqrt{y^{2}+10} ga hisoblang va y^{2}+10 ni qiymatni oling.

$$0\left(y^{2}+10+2\sqrt{y^{2}+10}y+y^{2}\right)-2$$

2y^{2} ni olish uchun y^{2} va y^{2} ni birlashtirish.

$$0\left(2y^{2}+10+2\sqrt{y^{2}+10}y\right)-2$$

0 ga 2y^{2}+10+2\sqrt{y^{2}+10}y ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$3\times 0-2$$

0 hosil qilish uchun 3 va 0 ni ko'paytirish.

$$0-2$$

-2 olish uchun 0 dan 2 ni ayirish.

$$-2$$

Omil

$$-2$$