0=10-98x^2 eching

$$0=10-98 { x }^{ 2 }$$

x uchun yechish

$$x=\frac{\sqrt{5}}{7}\approx 0,319438282$$

$$x=-\frac{\sqrt{5}}{7}\approx -0,319438282$$

Kvadrat ildizini topish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$10-98x^{2}=0$$

Ikkala tarafdan 10 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$-98x^{2}=-10$$

Ikki tarafini -98 ga bo‘ling.

$$x^{2}=\frac{-10}{-98}$$

\frac{-10}{-98} ulushini -2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x^{2}=\frac{5}{49}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\frac{\sqrt{5}}{7} x=-\frac{\sqrt{5}}{7}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$10-98x^{2}=0$$

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$-98x^{2}+10=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -98 ni a, 0 ni b va 10 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-98\right)\times 10}}{2\left(-98\right)}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-98\right)\times 10}}{2\left(-98\right)}$$

-4 ni -98 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{392\times 10}}{2\left(-98\right)}$$

392 ni 10 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{3920}}{2\left(-98\right)}$$

3920 ning kvadrat ildizini chiqarish.

$$x=\frac{0±28\sqrt{5}}{2\left(-98\right)}$$

2 ni -98 marotabaga ko'paytirish.

$$x=\frac{0±28\sqrt{5}}{-196}$$

x=\frac{0±28\sqrt{5}}{-196} tenglamasini yeching, bunda ± musbat.

$$x=-\frac{\sqrt{5}}{7}$$

x=\frac{0±28\sqrt{5}}{-196} tenglamasini yeching, bunda ± manfiy.

$$x=\frac{\sqrt{5}}{7}$$

Tenglama yechildi.

$$x=-\frac{\sqrt{5}}{7} x=\frac{\sqrt{5}}{7}$$