-4-2x^2=-2 eching

$$-4-2 { x }^{ 2 } =-2$$

x uchun yechish (complex solution)

$$x=-i$$

$$x=i$$

Kvadrat ildizini topish bo'yicha qadamlar

4 ni ikki tarafga qo’shing.

$$-2x^{2}=-2+4$$

2 olish uchun -2 va 4'ni qo'shing.

$$-2x^{2}=2$$

Ikki tarafini -2 ga bo‘ling.

$$x^{2}=\frac{2}{-2}$$

-1 ni olish uchun 2 ni -2 ga bo‘ling.

$$x^{2}=-1$$

Tenglama yechildi.

$$x=i x=-i$$

Kvadrat tenglamalaridan foydalanish qoidalari

2 ni ikki tarafga qo’shing.

$$-4-2x^{2}+2=0$$

-2 olish uchun -4 va 2'ni qo'shing.

$$-2-2x^{2}=0$$

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$-2x^{2}-2=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -2 ni a, 0 ni b va -2 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-2\right)\left(-2\right)}}{2\left(-2\right)}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-2\right)\left(-2\right)}}{2\left(-2\right)}$$

-4 ni -2 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{8\left(-2\right)}}{2\left(-2\right)}$$

8 ni -2 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-16}}{2\left(-2\right)}$$

-16 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4i}{2\left(-2\right)}$$

2 ni -2 marotabaga ko'paytirish.

$$x=\frac{0±4i}{-4}$$

x=\frac{0±4i}{-4} tenglamasini yeching, bunda ± musbat.

$$x=-i$$

x=\frac{0±4i}{-4} tenglamasini yeching, bunda ± manfiy.

$$x=i$$

Tenglama yechildi.

$$x=-i x=i$$