-2x^2-5x+1 eching

$$-2 { x }^{ 2 } -5x+1$$

Omil

$$-2\left(x-\frac{-\sqrt{33}-5}{4}\right)\left(x-\frac{\sqrt{33}-5}{4}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-2x^{2}-5x+1=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-5\right)±\sqrt{\left(-5\right)^{2}-4\left(-2\right)}}{2\left(-2\right)}$$

-5 kvadratini chiqarish.

$$x=\frac{-\left(-5\right)±\sqrt{25-4\left(-2\right)}}{2\left(-2\right)}$$

-4 ni -2 marotabaga ko'paytirish.

$$x=\frac{-\left(-5\right)±\sqrt{25+8}}{2\left(-2\right)}$$

25 ni 8 ga qo'shish.

$$x=\frac{-\left(-5\right)±\sqrt{33}}{2\left(-2\right)}$$

-5 ning teskarisi 5 ga teng.

$$x=\frac{5±\sqrt{33}}{2\left(-2\right)}$$

2 ni -2 marotabaga ko'paytirish.

$$x=\frac{5±\sqrt{33}}{-4}$$

x=\frac{5±\sqrt{33}}{-4} tenglamasini yeching, bunda ± musbat. 5 ni \sqrt{33} ga qo'shish.

$$x=\frac{\sqrt{33}+5}{-4}$$

5+\sqrt{33} ni -4 ga bo'lish.

$$x=\frac{-\sqrt{33}-5}{4}$$

x=\frac{5±\sqrt{33}}{-4} tenglamasini yeching, bunda ± manfiy. 5 dan \sqrt{33} ni ayirish.

$$x=\frac{5-\sqrt{33}}{-4}$$

5-\sqrt{33} ni -4 ga bo'lish.

$$x=\frac{\sqrt{33}-5}{4}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-5-\sqrt{33}}{4} ga va x_{2} uchun \frac{-5+\sqrt{33}}{4} ga bo‘ling.

$$-2x^{2}-5x+1=-2\left(x-\frac{-\sqrt{33}-5}{4}\right)\left(x-\frac{\sqrt{33}-5}{4}\right)$$

Baholash

$$1-5x-2x^{2}$$