-2x^2=1 eching

$$-2 { x }^{ 2 } =1$$

x uchun yechish (complex solution)

$$x=-\frac{\sqrt{2}i}{2}\approx -0-0,707106781i$$

$$x=\frac{\sqrt{2}i}{2}\approx 0,707106781i$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikki tarafini -2 ga bo‘ling.

$$x^{2}=-\frac{1}{2}$$

Tenglama yechildi.

$$x=\frac{\sqrt{2}i}{2} x=-\frac{\sqrt{2}i}{2}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikki tarafini -2 ga bo‘ling.

$$x^{2}=-\frac{1}{2}$$

\frac{1}{2} ni ikki tarafga qo’shing.

$$x^{2}+\frac{1}{2}=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va \frac{1}{2} ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times \frac{1}{2}}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times \frac{1}{2}}}{2}$$

-4 ni \frac{1}{2} marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-2}}{2}$$

-2 ning kvadrat ildizini chiqarish.

$$x=\frac{0±\sqrt{2}i}{2}$$

x=\frac{0±\sqrt{2}i}{2} tenglamasini yeching, bunda ± musbat.

$$x=\frac{\sqrt{2}i}{2}$$

x=\frac{0±\sqrt{2}i}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\frac{\sqrt{2}i}{2}$$

Tenglama yechildi.

$$x=\frac{\sqrt{2}i}{2} x=-\frac{\sqrt{2}i}{2}$$