-2x^2+17x+39 eching

$$-2 { x }^{ 2 } +17x+39$$

Omil

$$-2\left(x-\frac{17-\sqrt{601}}{4}\right)\left(x-\frac{\sqrt{601}+17}{4}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-2x^{2}+17x+39=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-17±\sqrt{17^{2}-4\left(-2\right)\times 39}}{2\left(-2\right)}$$

17 kvadratini chiqarish.

$$x=\frac{-17±\sqrt{289-4\left(-2\right)\times 39}}{2\left(-2\right)}$$

-4 ni -2 marotabaga ko'paytirish.

$$x=\frac{-17±\sqrt{289+8\times 39}}{2\left(-2\right)}$$

8 ni 39 marotabaga ko'paytirish.

$$x=\frac{-17±\sqrt{289+312}}{2\left(-2\right)}$$

289 ni 312 ga qo'shish.

$$x=\frac{-17±\sqrt{601}}{2\left(-2\right)}$$

2 ni -2 marotabaga ko'paytirish.

$$x=\frac{-17±\sqrt{601}}{-4}$$

x=\frac{-17±\sqrt{601}}{-4} tenglamasini yeching, bunda ± musbat. -17 ni \sqrt{601} ga qo'shish.

$$x=\frac{\sqrt{601}-17}{-4}$$

-17+\sqrt{601} ni -4 ga bo'lish.

$$x=\frac{17-\sqrt{601}}{4}$$

x=\frac{-17±\sqrt{601}}{-4} tenglamasini yeching, bunda ± manfiy. -17 dan \sqrt{601} ni ayirish.

$$x=\frac{-\sqrt{601}-17}{-4}$$

-17-\sqrt{601} ni -4 ga bo'lish.

$$x=\frac{\sqrt{601}+17}{4}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{17-\sqrt{601}}{4} ga va x_{2} uchun \frac{17+\sqrt{601}}{4} ga bo‘ling.

$$-2x^{2}+17x+39=-2\left(x-\frac{17-\sqrt{601}}{4}\right)\left(x-\frac{\sqrt{601}+17}{4}\right)$$

Baholash

$$39+17x-2x^{2}$$