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-12x^{2}-2052x+1454544=0
Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.
x=\frac{-\left(-2052\right)±\sqrt{\left(-2052\right)^{2}-4\left(-12\right)\times 1454544}}{2\left(-12\right)}
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-\left(-2052\right)±\sqrt{4210704-4\left(-12\right)\times 1454544}}{2\left(-12\right)}
-2052 kvadratini chiqarish.
x=\frac{-\left(-2052\right)±\sqrt{4210704+48\times 1454544}}{2\left(-12\right)}
-4 ni -12 marotabaga ko'paytirish.
x=\frac{-\left(-2052\right)±\sqrt{4210704+69818112}}{2\left(-12\right)}
48 ni 1454544 marotabaga ko'paytirish.
x=\frac{-\left(-2052\right)±\sqrt{74028816}}{2\left(-12\right)}
4210704 ni 69818112 ga qo'shish.
x=\frac{-\left(-2052\right)±8604}{2\left(-12\right)}
74028816 ning kvadrat ildizini chiqarish.
x=\frac{2052±8604}{2\left(-12\right)}
-2052 ning teskarisi 2052 ga teng.
x=\frac{2052±8604}{-24}
2 ni -12 marotabaga ko'paytirish.
x=\frac{10656}{-24}
x=\frac{2052±8604}{-24} tenglamasini yeching, bunda ± musbat. 2052 ni 8604 ga qo'shish.
x=-444
10656 ni -24 ga bo'lish.
x=-\frac{6552}{-24}
x=\frac{2052±8604}{-24} tenglamasini yeching, bunda ± manfiy. 2052 dan 8604 ni ayirish.
x=273
-6552 ni -24 ga bo'lish.
-12x^{2}-2052x+1454544=-12\left(x-\left(-444\right)\right)\left(x-273\right)
ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -444 ga va x_{2} uchun 273 ga bo‘ling.
-12x^{2}-2052x+1454544=-12\left(x+444\right)\left(x-273\right)
p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.