-(x+1)(-1)(x-1)=8 eching

$$-(x+1)(-1)(x-1)=8$$

x uchun yechish

$$x=-3$$

$$x=3$$

Kvadrat ildizini topish bo'yicha qadamlar

x+1 teskarisini topish uchun har birining teskarisini toping.

$$\left(-x-1\right)\left(-1\right)\left(x-1\right)=8$$

-x-1 ga -1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(x+1\right)\left(x-1\right)=8$$

Hisoblang: \left(x+1\right)\left(x-1\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$x^{2}-1^{2}=8$$

2 daraja ko‘rsatkichini 1 ga hisoblang va 1 ni qiymatni oling.

$$x^{2}-1=8$$

1 ni ikki tarafga qo’shing.

$$x^{2}=8+1$$

9 olish uchun 8 va 1'ni qo'shing.

$$x^{2}=9$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=3 x=-3$$

Kvadrat tenglamalaridan foydalanish qoidalari

x+1 teskarisini topish uchun har birining teskarisini toping.

$$\left(-x-1\right)\left(-1\right)\left(x-1\right)=8$$

-x-1 ga -1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(x+1\right)\left(x-1\right)=8$$

Hisoblang: \left(x+1\right)\left(x-1\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$x^{2}-1^{2}=8$$

2 daraja ko‘rsatkichini 1 ga hisoblang va 1 ni qiymatni oling.

$$x^{2}-1=8$$

Ikkala tarafdan 8 ni ayirish.

$$x^{2}-1-8=0$$

-9 olish uchun -1 dan 8 ni ayirish.

$$x^{2}-9=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -9 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-9\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-9\right)}}{2}$$

-4 ni -9 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{36}}{2}$$

36 ning kvadrat ildizini chiqarish.

$$x=\frac{0±6}{2}$$

x=\frac{0±6}{2} tenglamasini yeching, bunda ± musbat. 6 ni 2 ga bo'lish.

$$x=3$$

x=\frac{0±6}{2} tenglamasini yeching, bunda ± manfiy. -6 ni 2 ga bo'lish.

$$x=-3$$

Tenglama yechildi.

$$x=3 x=-3$$