-x^3+Ax^2=B eching

$$- x ^ { 3 } + A x ^ { 2 } = B$$

A uchun yechish (complex solution)

$$\left\{\begin{matrix}A=x+\frac{B}{x^{2}}\text{, }&x\neq 0\\A\in \mathrm{C}\text{, }&B=0\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x^{3} ni ikki tarafga qo’shing.

$$Ax^{2}=B+x^{3}$$

Tenglama standart shaklda.

$$x^{2}A=x^{3}+B$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}A}{x^{2}}=\frac{x^{3}+B}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$A=\frac{x^{3}+B}{x^{2}}$$

B+x^{3} ni x^{2} ga bo'lish.

$$A=x+\frac{B}{x^{2}}$$

A uchun yechish

$$\left\{\begin{matrix}A=x+\frac{B}{x^{2}}\text{, }&x\neq 0\\A\in \mathrm{R}\text{, }&x=0\text{ and }B=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x^{3} ni ikki tarafga qo’shing.

$$Ax^{2}=B+x^{3}$$

Tenglama standart shaklda.

$$x^{2}A=x^{3}+B$$

Ikki tarafini x^{2} ga bo‘ling.

$$\frac{x^{2}A}{x^{2}}=\frac{x^{3}+B}{x^{2}}$$

x^{2} ga bo'lish x^{2} ga ko'paytirishni bekor qiladi.

$$A=\frac{x^{3}+B}{x^{2}}$$

B+x^{3} ni x^{2} ga bo'lish.

$$A=x+\frac{B}{x^{2}}$$

B uchun yechish

$$B=\left(A-x\right)x^{2}$$