-x^2+2x+5 eching

$$- x ^ { 2 } + 2 x + 5$$

Omil

$$-\left(x-\left(1-\sqrt{6}\right)\right)\left(x-\left(\sqrt{6}+1\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-x^{2}+2x+5=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-2±\sqrt{2^{2}-4\left(-1\right)\times 5}}{2\left(-1\right)}$$

2 kvadratini chiqarish.

$$x=\frac{-2±\sqrt{4-4\left(-1\right)\times 5}}{2\left(-1\right)}$$

-4 ni -1 marotabaga ko'paytirish.

$$x=\frac{-2±\sqrt{4+4\times 5}}{2\left(-1\right)}$$

4 ni 5 marotabaga ko'paytirish.

$$x=\frac{-2±\sqrt{4+20}}{2\left(-1\right)}$$

4 ni 20 ga qo'shish.

$$x=\frac{-2±\sqrt{24}}{2\left(-1\right)}$$

24 ning kvadrat ildizini chiqarish.

$$x=\frac{-2±2\sqrt{6}}{2\left(-1\right)}$$

2 ni -1 marotabaga ko'paytirish.

$$x=\frac{-2±2\sqrt{6}}{-2}$$

x=\frac{-2±2\sqrt{6}}{-2} tenglamasini yeching, bunda ± musbat. -2 ni 2\sqrt{6} ga qo'shish.

$$x=\frac{2\sqrt{6}-2}{-2}$$

-2+2\sqrt{6} ni -2 ga bo'lish.

$$x=1-\sqrt{6}$$

x=\frac{-2±2\sqrt{6}}{-2} tenglamasini yeching, bunda ± manfiy. -2 dan 2\sqrt{6} ni ayirish.

$$x=\frac{-2\sqrt{6}-2}{-2}$$

-2-2\sqrt{6} ni -2 ga bo'lish.

$$x=\sqrt{6}+1$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 1-\sqrt{6} ga va x_{2} uchun 1+\sqrt{6} ga bo‘ling.

$$-x^{2}+2x+5=-\left(x-\left(1-\sqrt{6}\right)\right)\left(x-\left(\sqrt{6}+1\right)\right)$$

Baholash

$$5+2x-x^{2}$$