-b^2x^2+ax+4=0 eching

$$- b ^ { 2 } x ^ { 2 } + a x + 4 = 0$$

a uchun yechish

$$a=\frac{\left(bx\right)^{2}-4}{x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan \left(-b^{2}\right)x^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$ax+4=-\left(-b^{2}\right)x^{2}$$

Ikkala tarafdan 4 ni ayirish.

$$ax=-\left(-b^{2}\right)x^{2}-4$$

1 hosil qilish uchun -1 va -1 ni ko'paytirish.

$$ax=b^{2}x^{2}-4$$

Tenglama standart shaklda.

$$xa=b^{2}x^{2}-4$$

Ikki tarafini x ga bo‘ling.

$$\frac{xa}{x}=\frac{b^{2}x^{2}-4}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$a=\frac{b^{2}x^{2}-4}{x}$$

b^{2}x^{2}-4 ni x ga bo'lish.

$$a=xb^{2}-\frac{4}{x}$$

b uchun yechish (complex solution)

$$b=-\frac{\sqrt{ax+4}}{x}$$

$$b=\frac{\sqrt{ax+4}}{x}\text{, }x\neq 0$$

b uchun yechish

$$b=\frac{\sqrt{ax+4}}{|x|}$$

$$b=-\frac{\sqrt{ax+4}}{|x|}\text{, }\left(a\neq 0\text{ and }x=-\frac{4}{a}\right)\text{ or }\left(x\leq -\frac{4}{a}\text{ and }a\leq 0\text{ and }x\neq 0\right)\text{ or }\left(a\geq 0\text{ and }x\geq -\frac{4}{a}\text{ and }x\neq 0\right)\text{ or }\left(a=0\text{ and }x\neq 0\right)$$