-6n-n^2 eching

$$- 6 n - n ^ { 2 }$$

Omil

$$-n\left(n+6\right)$$

Yechim qadamlari

n omili.

$$n\left(-6-n\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-n^{2}-6n=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$n=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}}}{2\left(-1\right)}$$

\left(-6\right)^{2} ning kvadrat ildizini chiqarish.

$$n=\frac{-\left(-6\right)±6}{2\left(-1\right)}$$

-6 ning teskarisi 6 ga teng.

$$n=\frac{6±6}{2\left(-1\right)}$$

2 ni -1 marotabaga ko'paytirish.

$$n=\frac{6±6}{-2}$$

n=\frac{6±6}{-2} tenglamasini yeching, bunda ± musbat. 6 ni 6 ga qo'shish.

$$n=\frac{12}{-2}$$

12 ni -2 ga bo'lish.

$$n=-6$$

n=\frac{6±6}{-2} tenglamasini yeching, bunda ± manfiy. 6 dan 6 ni ayirish.

$$n=\frac{0}{-2}$$

0 ni -2 ga bo'lish.

$$n=0$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -6 ga va x_{2} uchun 0 ga bo‘ling.

$$-n^{2}-6n=-\left(n-\left(-6\right)\right)n$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$-n^{2}-6n=-\left(n+6\right)n$$

Baholash

$$-n\left(n+6\right)$$