-5x(2y+4)-y=2 eching

$$- 5 x ( 2 y + 4 ) - y = 2$$

x uchun yechish (complex solution)

$$\left\{\begin{matrix}\\x=-\frac{1}{10}=-0,1\text{, }&\text{unconditionally}\\x\in \mathrm{C}\text{, }&y=-2\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-5x ga 2y+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-10xy-20x-y=2$$

y ni ikki tarafga qo’shing.

$$-10xy-20x=2+y$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-10y-20\right)x=2+y$$

Tenglama standart shaklda.

$$\left(-10y-20\right)x=y+2$$

Ikki tarafini -10y-20 ga bo‘ling.

$$\frac{\left(-10y-20\right)x}{-10y-20}=\frac{y+2}{-10y-20}$$

-10y-20 ga bo'lish -10y-20 ga ko'paytirishni bekor qiladi.

$$x=\frac{y+2}{-10y-20}$$

2+y ni -10y-20 ga bo'lish.

$$x=-\frac{1}{10}$$

y uchun yechish (complex solution)

$$\left\{\begin{matrix}\\y=-2\text{, }&\text{unconditionally}\\y\in \mathrm{C}\text{, }&x=-\frac{1}{10}\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-5x ga 2y+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-10xy-20x-y=2$$

20x ni ikki tarafga qo’shing.

$$-10xy-y=2+20x$$

y'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-10x-1\right)y=2+20x$$

Tenglama standart shaklda.

$$\left(-10x-1\right)y=20x+2$$

Ikki tarafini -1-10x ga bo‘ling.

$$\frac{\left(-10x-1\right)y}{-10x-1}=\frac{20x+2}{-10x-1}$$

-1-10x ga bo'lish -1-10x ga ko'paytirishni bekor qiladi.

$$y=\frac{20x+2}{-10x-1}$$

2+20x ni -1-10x ga bo'lish.

$$y=-2$$

x uchun yechish

$$\left\{\begin{matrix}\\x=-\frac{1}{10}=-0,1\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&y=-2\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-5x ga 2y+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-10xy-20x-y=2$$

y ni ikki tarafga qo’shing.

$$-10xy-20x=2+y$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-10y-20\right)x=2+y$$

Tenglama standart shaklda.

$$\left(-10y-20\right)x=y+2$$

Ikki tarafini -10y-20 ga bo‘ling.

$$\frac{\left(-10y-20\right)x}{-10y-20}=\frac{y+2}{-10y-20}$$

-10y-20 ga bo'lish -10y-20 ga ko'paytirishni bekor qiladi.

$$x=\frac{y+2}{-10y-20}$$

2+y ni -10y-20 ga bo'lish.

$$x=-\frac{1}{10}$$

y uchun yechish

$$\left\{\begin{matrix}\\y=-2\text{, }&\text{unconditionally}\\y\in \mathrm{R}\text{, }&x=-\frac{1}{10}\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-5x ga 2y+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-10xy-20x-y=2$$

20x ni ikki tarafga qo’shing.

$$-10xy-y=2+20x$$

y'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-10x-1\right)y=2+20x$$

Tenglama standart shaklda.

$$\left(-10x-1\right)y=20x+2$$

Ikki tarafini -1-10x ga bo‘ling.

$$\frac{\left(-10x-1\right)y}{-10x-1}=\frac{20x+2}{-10x-1}$$

-1-10x ga bo'lish -1-10x ga ko'paytirishni bekor qiladi.

$$y=\frac{20x+2}{-10x-1}$$

2+20x ni -1-10x ga bo'lish.

$$y=-2$$