-5x^2-2x eching

$$- 5 x ^ { 2 } - 2 x$$

Omil

$$-x\left(5x+2\right)$$

Yechim qadamlari

x omili.

$$x\left(-5x-2\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-5x^{2}-2x=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}}}{2\left(-5\right)}$$

\left(-2\right)^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-2\right)±2}{2\left(-5\right)}$$

-2 ning teskarisi 2 ga teng.

$$x=\frac{2±2}{2\left(-5\right)}$$

2 ni -5 marotabaga ko'paytirish.

$$x=\frac{2±2}{-10}$$

x=\frac{2±2}{-10} tenglamasini yeching, bunda ± musbat. 2 ni 2 ga qo'shish.

$$x=\frac{4}{-10}$$

\frac{4}{-10} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=-\frac{2}{5}$$

x=\frac{2±2}{-10} tenglamasini yeching, bunda ± manfiy. 2 dan 2 ni ayirish.

$$x=\frac{0}{-10}$$

0 ni -10 ga bo'lish.

$$x=0$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -\frac{2}{5} ga va x_{2} uchun 0 ga bo‘ling.

$$-5x^{2}-2x=-5\left(x-\left(-\frac{2}{5}\right)\right)x$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$-5x^{2}-2x=-5\left(x+\frac{2}{5}\right)x$$

Umumiy maxrajni topib va hisoblovchini qo'shish orqali \frac{2}{5} ni x ga qo'shing. So'ngra agar imkoni bo'lsa kasrni eng kam shartga qisqartiring.

$$-5x^{2}-2x=-5\times \frac{-5x-2}{-5}x$$

-5 va -5 ichida eng katta umumiy 5 faktorini bekor qiling.

$$-5x^{2}-2x=\left(-5x-2\right)x$$

Baholash

$$-x\left(5x+2\right)$$