-3p^2+12p eching

$$- 3 p ^ { 2 } + 12 p$$

Omil

$$3p\left(4-p\right)$$

Yechim qadamlari

3 omili.

$$3\left(-p^{2}+4p\right)$$

Hisoblang: -p^{2}+4p. p omili.

$$p\left(-p+4\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$3p\left(-p+4\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-3p^{2}+12p=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$p=\frac{-12±\sqrt{12^{2}}}{2\left(-3\right)}$$

12^{2} ning kvadrat ildizini chiqarish.

$$p=\frac{-12±12}{2\left(-3\right)}$$

2 ni -3 marotabaga ko'paytirish.

$$p=\frac{-12±12}{-6}$$

p=\frac{-12±12}{-6} tenglamasini yeching, bunda ± musbat. -12 ni 12 ga qo'shish.

$$p=\frac{0}{-6}$$

0 ni -6 ga bo'lish.

$$p=0$$

p=\frac{-12±12}{-6} tenglamasini yeching, bunda ± manfiy. -12 dan 12 ni ayirish.

$$p=-\frac{24}{-6}$$

-24 ni -6 ga bo'lish.

$$p=4$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun 4 ga bo‘ling.

$$-3p^{2}+12p=-3p\left(p-4\right)$$

Baholash

$$3p\left(4-p\right)$$