-3I_{A}+2I_{B}+I_{C}=-9 eching

$$- 3 I _ { A } + 2 I _ { B } + I _ { C } = - 9$$

I_A uchun yechish

$$I_{A}=\frac{2I_{B}+I_{C}+9}{3}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan 2I_{B} ni ayirish.

$$-3I_{A}+I_{C}=-9-2I_{B}$$

Ikkala tarafdan I_{C} ni ayirish.

$$-3I_{A}=-9-2I_{B}-I_{C}$$

Tenglama standart shaklda.

$$-3I_{A}=-2I_{B}-I_{C}-9$$

Ikki tarafini -3 ga bo‘ling.

$$\frac{-3I_{A}}{-3}=\frac{-2I_{B}-I_{C}-9}{-3}$$

-3 ga bo'lish -3 ga ko'paytirishni bekor qiladi.

$$I_{A}=\frac{-2I_{B}-I_{C}-9}{-3}$$

-9-2I_{B}-I_{C} ni -3 ga bo'lish.

$$I_{A}=\frac{I_{C}}{3}+\frac{2I_{B}}{3}+3$$

I_B uchun yechish

$$I_{B}=\frac{3I_{A}-I_{C}-9}{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

3I_{A} ni ikki tarafga qo’shing.

$$2I_{B}+I_{C}=-9+3I_{A}$$

Ikkala tarafdan I_{C} ni ayirish.

$$2I_{B}=-9+3I_{A}-I_{C}$$

Tenglama standart shaklda.

$$2I_{B}=3I_{A}-I_{C}-9$$

Ikki tarafini 2 ga bo‘ling.

$$\frac{2I_{B}}{2}=\frac{3I_{A}-I_{C}-9}{2}$$

2 ga bo'lish 2 ga ko'paytirishni bekor qiladi.

$$I_{B}=\frac{3I_{A}-I_{C}-9}{2}$$