-2(x-1)+3(4-x)=2(x-3)-5(2x+1) eching

$$- 2 ( x - 1 ) + 3 ( 4 - x ) = 2 ( x - 3 ) - 5 ( 2 x + 1 )$$

x uchun yechish

$$x = -\frac{25}{3} = -8\frac{1}{3} \approx -8,333333333$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-2 ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-2x+2+3\left(4-x\right)=2\left(x-3\right)-5\left(2x+1\right)$$

3 ga 4-x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-2x+2+12-3x=2\left(x-3\right)-5\left(2x+1\right)$$

14 olish uchun 2 va 12'ni qo'shing.

$$-2x+14-3x=2\left(x-3\right)-5\left(2x+1\right)$$

-5x ni olish uchun -2x va -3x ni birlashtirish.

$$-5x+14=2\left(x-3\right)-5\left(2x+1\right)$$

2 ga x-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-5x+14=2x-6-5\left(2x+1\right)$$

-5 ga 2x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-5x+14=2x-6-10x-5$$

-8x ni olish uchun 2x va -10x ni birlashtirish.

$$-5x+14=-8x-6-5$$

-11 olish uchun -6 dan 5 ni ayirish.

$$-5x+14=-8x-11$$

8x ni ikki tarafga qo’shing.

$$-5x+14+8x=-11$$

3x ni olish uchun -5x va 8x ni birlashtirish.

$$3x+14=-11$$

Ikkala tarafdan 14 ni ayirish.

$$3x=-11-14$$

-25 olish uchun -11 dan 14 ni ayirish.

$$3x=-25$$

Ikki tarafini 3 ga bo‘ling.

$$x=\frac{-25}{3}$$

\frac{-25}{3} kasri manfiy belgini olib tashlash bilan -\frac{25}{3} sifatida qayta yozilishi mumkin.

$$x=-\frac{25}{3}$$