-13x^2-13x eching

$$- 13 x ^ { 2 } - 13 x$$

Omil

$$-13x\left(x+1\right)$$

Yechim qadamlari

13 omili.

$$13\left(-x^{2}-x\right)$$

Hisoblang: -x^{2}-x. x omili.

$$x\left(-x-1\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$13x\left(-x-1\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-13x^{2}-13x=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-13\right)±\sqrt{\left(-13\right)^{2}}}{2\left(-13\right)}$$

\left(-13\right)^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-13\right)±13}{2\left(-13\right)}$$

-13 ning teskarisi 13 ga teng.

$$x=\frac{13±13}{2\left(-13\right)}$$

2 ni -13 marotabaga ko'paytirish.

$$x=\frac{13±13}{-26}$$

x=\frac{13±13}{-26} tenglamasini yeching, bunda ± musbat. 13 ni 13 ga qo'shish.

$$x=\frac{26}{-26}$$

26 ni -26 ga bo'lish.

$$x=-1$$

x=\frac{13±13}{-26} tenglamasini yeching, bunda ± manfiy. 13 dan 13 ni ayirish.

$$x=\frac{0}{-26}$$

0 ni -26 ga bo'lish.

$$x=0$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -1 ga va x_{2} uchun 0 ga bo‘ling.

$$-13x^{2}-13x=-13\left(x-\left(-1\right)\right)x$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$-13x^{2}-13x=-13\left(x+1\right)x$$

Baholash

$$-13x\left(x+1\right)$$